[size=36]Integrity: bringing in a deputy accused of receiving $750,000 in exchange for refraining from exercising his oversight work[/size]
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The Federal Integrity Commission announced today, Wednesday, the issuance of a decision to recruit a member of the House of Representatives for the current session on charges of "bribery".
According to a statement received by Mawazine News, the Commission's Investigation Department stated, "The investigative commission issued a decision to recruit a member of the current House of Representatives," noting that "the decision was issued as a result of his accusation of receiving 750,000 dollars - jointly with another former deputy - from a businessman; In exchange for not raising corruption files related to his companies.
The department noted, "The investigative body issued a decision to recruit, based on the provisions of Resolution (160 of 1983), while the decision also included notifying the House of Representatives, in order to lift his immunity, and providing it with information regarding the other former deputy accused of participating with him in the same case." Ended 29/N33